A particle executing simple harmonic motion comes to rest at the extreme positions. Is the resultant force on the particle zero at these positions asccording to Newton's first law?

If particle is excuting simple harmonic motion with time period T, then the time period of its total mechanical energy is :-

A particle executes simple harmonic motion with frequency f. The frequency of its potential and kinetic energy is………

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm"/"s . The frequency of its oscillation is……….

A particle executes simple harmonic motion with an amplitude A. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude form the equilibrium position is………..

Explain by plats the position of particle executing simple harmonic motion at different time.

A particle executes simple harmonic motion with a period of 16s . At time t=2s , the particle crosses the mean position while at t=4s , its velocity is 4ms^-1 amplitude of motion in metre is

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in second is…….

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=0 ?

Position-time relationship of a particle executing simple harmonic motion is given by equation x=2sin(50pit+(2pi)/(3)) where x is in meters and time t is in seconds. What is the position of particle at t=1s ?

The motion of a particle executing simple harmonic motion is described by the displacement function, x(t)=Acos(omegat+phi) . If the initial (t = 0) position of the particle is 1 cm and its initial velocity is omega cm/s, what are its amplitude and initial phase angle ? The angular frequency of the particle is pi s^(-1) . If instead of the cosine function, we choose the sine function to describe the SHM : x = B sin (omegat + alpha) , what are the amplitude and initial phase of the particle with the above initial conditions.