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(1 microm /1 fm) =...

(1 `microm` /1 `fm`) =

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The correct Answer is:
So, at `pi/120 ` sec it first comes to rest
`t=pi/30sec`
`rarr t=pi/30sec`
`x=5(20t+pi/3)`
a. Max displacement from the mean position = Amplitude of the particle.
At the extreme position the velocity becomes 0
`:. x=5=Amplitude`
`:. 5=5sin(20t+pi/3)`
`sin(20t+pi/3)=1=sinpi/2`
`rarr 20t+pi/3=pi/2`
`rarr t=pi/120sec`e
`So, at pi/120 ` sec it first comes to rest
`b. a=omega^2x`
`=omega^2[5sin(20t+pi/3)]`
Fro `a=0,`
`5sin(20t+pi/3)=0`
`rarr sin(20t+pi/3)=sinx`
`rarr 20t=pi-pi/3=(2pi)/3`
`t=pi/30sec`
c. `v=Aomegacos(omegat+pi/3)` lt. when omega is maximum i.e. `cos(20t+pi/3)=-1=cospi`
`20t=pi-pi/3=(2pi)/3`
`rarr t=pi/30sec`
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