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1nm =micro meter...

1nm =__micro meter

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The correct Answer is:
B
When the block A moves with velocity V and collides with the block B, it transfers all energy to the block B. (because it is an elastic collision). The block A will move a distance x against the spring, again the spring, again the block b will return to the origiN/Al point and completes half of the oscillation.
So, the time period of b is
`(2pisqrt(m/k))/2=m/k`
The block B collides with the block A and comes o rest at that point. The block AS again moves a further distance L to return to its origiN/Al position. The time taken is
`L/V+L/V=2(L/V)`
So the period of the periodic motion is
`2L/V+pi sqrt((m/k))`
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