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If a perfect square is 144 then its root...

If a perfect square is 144 then its root would lie in the range _____
a) 10 and 13
b) 13 and 15
c) 5 and 10
d) 12 and 16

Text Solution

Verified by Experts

The correct Answer is:
`=9.795m/s^2`
For the pendulum
`T_1/T_2=sqrt((g_2/g_1))`
Given that `T_2=2sec, g_1=9.8m/s^2`
`T_1=(24xx3600)/((24xx360xx-24)/2)`
`=2xx3600/3599`
now `(g_2/g_1)=(T_1/T_2)^2`
`:. g_2=(9.8)(3599/3600)^2`
`=9.795m/s^2`
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