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The area of cross section of the wider t...

The area of cross section of the wider tube shown in figure is `900 cm^2`. If the boy standing on the piston weights 45 kg, find the difference in the levels of water in the two tubes.

Text Solution

Verified by Experts

The correct Answer is:
C
`P_1-P_2pgh`
`mg=1000xxgxxhA`
`rarr h=m/(1000xxA)`
`=45/(1000xx900xx10^-4)`
`=1/2m=50cm`
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