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A steel rod of cross sectional area 4cm^...

A steel rod of cross sectional area `4cm^2 and `length 2m shrinks by 0.1 cm as the temperature decreases in night. If the rod is clamped at both ends during the day horus, find the tension developed in it during night hours. Young modulus of steel `=1.9xx10^11` `nm^-2`

Text Solution

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The correct Answer is:
A, C, D
`A=4cm^2=4x10^-4, L=2m`
`=/_\L=0.1cm=10^-3, Y=1.9xx10^11`
`Y=F/AxxL/(/_\L)`
`rarr F=(YA/_\L)/L`
`(1.9xx10^11xx4xx10^-4xx10^-3)/2`
`=3.8xx10^4N`
The tension developed is `3.8xx10^4N`
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