Home
Class 11
PHYSICS
A drop of mercury of radius 2 mm is spli...

A drop of mercury of radius 2 mm is split into 8 identical droplets. Find the increase in surface energy. Surface tension of mercury `=0.465Jm^-2`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`r=2mm=2xx10^-3m,`
`T=0.465Jm^2`
`Volume of initial drop =8x(vol. of small drops)`
`=(4/3)piR^3=(4/3)pr^3xx8`
`=r=R/2=2`
Increase is surfac energy
`=TA\'-TA=8xx4pi^2T-4piR^2T`
`=4piT[98xx(R^2/4)-R^2]`
`=4piTR^2`
`=4xx(3.14)xx(0.465)xx(4xx10^-6)`
`=23.36 muJ`
Promotional Banner

Similar Questions

Explore conceptually related problems

A drop of liquid of diameter 2.8 mm split into 125 identical drops .The change in energy is …..(Surface tension T=75dyne/cm)

Diameters of the arms of a U tube are 10 mm and 1 mm . It is partially filled with water and it is held in a vertical plane . Find the difference in heights of water in both the arms . (Surface tension of water =70 dyne cm^(-1) angle of contact =0^(@).g=980cms^(-2))

A water drop of radius 1 mm is broken into 10^(6) identical drops, surface tension of water is 72 dynes/cm find the energy spent in this process.

Two mercury droplets of radii 0.1 cm . And 0.2 cm . Collapse into one single drop .What amount of energy is released ? The surface tension of mercury T=435.5xx10^(-3)Nm^(-1)

Mercury has an angle of contact equal to 140^(@) with soda lime glass . A narrow tube of radius 1.00 mm made of this glass is dipped in a trough containing mercury .By what amount does the mercury dip down in the tube relative to the liquid surface outside ? Surface tension of mercury at the temperature of the experiment is 0.465Nm^(-1) . Density of mercury =13.6xx10^(3)kgm^(-3)

Two small drops of mercury each of radius r coalesce to form a single large drop of radius R. The ratio of the total surface energies before and after the change is ……

Find the pressure in a bubble of radius 0.2 cm formed at the depth of 5cm from the free surface of water . The surface tension of water is 70 dyne cm^(-1) and its density is 1gcm^(-3) . Atmospheric pressure is 10^(6) dyne cm^(-2) .The gravitational acceleration is 980cms^(-2) .

Two mercury drops (each of radius r) merge to form a bigger drop. The surface energy of the bigger drop, if T is the surface tension is

Find the radius of a sphere whose surface area is 154 cm^(2) .