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Two successive resonant frequencies in a...

Two successive resonant frequencies in an open organ pipe are 1944 and 2592 Hz. If the speed of sound in air `324 ms^(-1)`, then find the length of tube.

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The correct Answer is:
B, C
Let the length of the resoN/Ating column will be =I
Here `v=320 m/s
Then the two successie resoN/Ance
frequencies are((n+1))/(4I) and (nv)/(4I)`
Here given `((n+1)v)/(4I)=2592`
`=lamda =(nv)/(4I)=2592`
`lamda=(nv)/(4I)=1944`
`rarr((n+1)v)/(4I)-(nv)/(4I)=2592-1944=548`
`rarr v/(4I)=548`
`rarr I=(320xx100)/(4x548)cm=25cm`
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