Home
Class 11
PHYSICS
Calculate the time required to heat 20 k...

Calculate the time required to heat 20 kg of water from `10^(@)C` to `35^(@)C` using an immersion heater rated 1000 W. Assume that `80%` of the power input is used to heat the water. Specific heat capacity of water`=4200 J//kg-k`

Text Solution

Verified by Experts

The correct Answer is:
D
Total heat required to raine the temperature of `20kg` of water from `10^(@)C to 35^(@)C`
`= 20 xx 4200 xx 25`
` = 20 xx 4200 xx 25 = 21 xx 10^(6)J`
Energy utilized ` = t xx (0.080) xx 1000`
Equation now, we get
`t = (21 xx 10^(5))/(800) = 44 min`
Promotional Banner

Similar Questions

Explore conceptually related problems

200 g of water is heated from 40^(@)C "to" 60^(@)C . Ignoring the slight expansion of water , the change in its internal energy is closed to (Given specific heat of water = 4184 J//kg//K ):

Calculate the heat required to convert 3 kg of ice at -12" "^(@)C kept in a calorimeter to steam at 100" "^(@)C at atmospheric pressure. Given specific heat capacity of ice =2100" J kg"^(-1)K^(-1) , specific heat capacity of water =4186" J kg"^(-1)K^(-1) , latent heat of fusionn of ice =3.35xx10^(5)" J kg"^(-1) and latent heat of steam =2.256xx10^(6)" J kg"^(-1) .

What will be the difference in volume of water when it is heated from 0^(@)C to 10^(@)C ?

100g of water is heated from 30^@C to 50^@C . Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4184J//kg//K ):

A refrigerator converts 100 g of water at 25^(@)C into ice at -10^(@)C in one hour and 50 minutes. The quantity of heat removed per minute is (specific heat of ice = 0.5 "cal"//g^(@)C , latent heat of fusion = 80 "cal"//g )

A refrigerator converts 100 g of water at 25^(@)C into ice at -10^(@)C in one hour and 50 minutes. The quantity of heat removed per minute is (specific heat of ice = 0.5 "cal"//g^(@)C , latent heat of fusion = 80 "cal"//g )

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

2kg of ice at 20^@C is mixed with 5kg of water at 20^@C in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water & ice are 1kcal//kg//^@C and 0.5 kcal//kg//^@C while the latent heat of fusion of ice is 80kcal//kg

A sphere of aluminium of 0.047 kg placed for sufficient time in a vessel containing boiling water, so that sphere is at 100" "^(@)C . It is then immediately transferred to 0.14 kg copper calorimeter containing 0.25 kg of water at 20" "^(@)C . The temperature of water rises and attains a steady state at 23" "^(@)C . Calculate the specific heat capacity of aluminium.