Suppose the second charge in the previous problem is `-1.0 xx 10^(-6) C.` Locate the position where a third charge will not experience a net force.

Explanation

`q_1=2xx10^-6C `
` q_2=-1xx10^-6C `
` R=10cm=10xx10^-2m, `
` Let the third charge be 'a' `
` So, F_(ac)=-F_(bc) `
` rArr 2c^2=(10+c)^2 `
` c=24.14 `
So distance of charge placed at x
` =(24.14+10)=34.14cm `
from larger charge.