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Consider a gold nucleus to be a sphere of redius 6.9 fermi in whichprotons and neutrons are distributed. Find the force of repulsion between two protons situated at largest separaton. Why do thes protons not fly apart under this repulsion

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The largest separation between two Protons be `=2r=fermi `
` So, F=9xx10^9xx(1.6xx10^-19)^2/(2r)^2=1.2N.`
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