A particle A having a charge of `2.0xx 10^(-6)` C and a mass of 100 g is placed at the bottom of a smoth inclined plane of inclination `30@` . Where should another particle B, having same charge and mass, be placed on the incline so that it may remain in equilibrium?

Explanation

`Q_a=2xx10^5C, M_B=80g `
Let the distance be R unit
For equillibrium
` F_e=mgsintheta `
` rArr =mxx9.8xx(1)/2 `
` R_2=7.34xx10^-2m `
` rArr R=2.70924xx10^-1m `
from the bottom