Two parallel plate capacitors, each of capacitance `40 muF` are connected is series. The space between the plates of one capacitor is filled with a dielectric material of dielectric constant K =4. Find the equivalent capacitance of the system.
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The capacitance of the capacitor with the dielectric is s` ` C_1 = KC_0 = 4X 40 muF = 160 mu F` `. The other capacitor has capacitance ` `C_2 = 40 um F` `. As they are connected in series, the equivalent capacitance is ` ` C = (C_1 C_2)/(C_1+C_2) = ((160 muF)(40 muF))/(200muF) = 32muF` `.
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