The plates of a parallel-plate capacior are given equal positive charges .What will be the potential difference between the plates ? What will be the charges on the facing surfaces and on the outer surfaces ?

A battery is used to charge a parallel plate capacitor till the potential difference between the plates become equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work clone by the battery will be .......

A moving positive charge approaches a negative charge. What will happen to the potential energy of the system?

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (½) QE, where Q is the charge on the capacitor, and E is the magnitude of electric Held between the plates. Explain the origin of the factor 1//2

Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (1//2) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor 1//2 .

What is the area of the plates of a 2 F parallel plate capacitor given that the separation between the plates is 0.5 cm ?

A metallic spherical shell has an inner radius R j and outer radius R_2 . A charge Q is placed at the centre of the spherical cavity. What will be surface charge density on (i) the inner surface, and (ii) the outer surface ?

A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor but has a thickless (1/2)d . Where d is the separation of the plates . How is the capacitance changed when the slab is inserted between the plates