A parallel -plate capacitor having plate area `25cm^2` and separation 1.00 mm is connected to a battery of `6.0V` . Calculate the charge flown through the battery . How much work has been done by the battery during the process ?

Explanation

`A = 25.0 xx 10^(-4) m^(2), d = 1 xx 10^(-3) m `
`C = eplision_0 A / d `
`= 8.88 xx 10^(-12) xx 25 xx10^(-4) / 1 xx 10^(-3)`
`= 2.22 xx 10^(-11) F`
charge `theta = CV = 2.22 xx 10^(-11) xx 6.0`
`= 1.33 xx 10^(-10) C`
work done `= QV`
`= 1.33 xx 10^(-10) J`.