Home
Class 12
PHYSICS
A current of 30 A is registered when the...

A current of `30 A` is registered when the terminals of a dry cell of `emf 1.5 Volts` are connected through an ammeter. Neglecting the meter resistance, find the amount of heat produced in the battery in 10 seconds.

Text Solution

Verified by Experts

The current in the circuit will be
`I = epsilon/r`
or, `30A = (1.5V)/r` giving `r = 0.05 Omega`.
The amount of heat produced in the battery `i^2 rt = (30A)^2 xx (0.5 Omega) xx 10s = 450 J`.
Promotional Banner

Topper's Solved these Questions

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA|Exercise Short Answer|9 Videos

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA|Exercise Objective 1|8 Videos

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA|Exercise Exercises|24 Videos

  • THE SPECIAL THEORY OF RELATIVITY

    HC VERMA|Exercise Exercises|27 Videos

  • X-Rays

    HC VERMA|Exercise Exercises|27 Videos

Similar Questions

Explore conceptually related problems

The potential difference between the terminals of a cells is found to be 3 volts when it is connected to a resistance equal to its internal resistance. The e.m.f. of the cell is:-

A current of 2 A flows through a 2 Omega resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 Omega resistor. The internal resistance of the battery is

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.

In a potenliomcter experiment, it is found that no current passes through the galvanometer when the terminals of the cell are connected across 52 cm of the potentiometer wire. If the cells is shunted by a resistance of 5 Omega , a balance is found when the cells is connected across 40 cm of the wire. Find the internal resistance of the cell.

A current of 1A flows in a series circuit containing an electric lamp and a conducor of 5 Omega connected to a 10V battery. Calculate the resistance of the electric lamp. Now if a resistance 10Omega is connected in parallel with this series combination, what change (if any)incurrent flowing through 5Omega conductor and potential difference across the lam will take palce ? Give the reason.

A cell sends a current through a resistance R_(1) for time t , next the same cell sends current through another resistance R_(2) for the time t If the same amount of heat is developed in both the resistance then find the internal resistance of the cell

When connected across the terminals of a cell, a voltmeter measures 5 V and a connected ammeter measures 10 A of current. A resistance of 2 ohm s is connected across the terminals of the cell. The current flowing through this resistance will be

A current of two amperes is flowing through a cell of e.m.f. 5 volts and internal resistance 0.5 ohm from negative to positive electrode. If the potential of negative electrode is 10 V , the potential of positive electrode will be

The potential difference between the terminals or a battery is 10 V and internal resistance 1 Omega drops to 8 V when connected across an external resistor . Find the resistance of the external resistor.

A group of N cells whose emf varies directly with the internal resistance as per the equation E_(N)=1.5r_(N ) are connected as shown in the figure. The current in the circuit is