An electric bulb marked `220 V, 100 W` will get fused if it is made to consume `150 W` or more. What voltage fluctuation will the bulb withstand?

Answer

B

Explanation

`V = 220 V`
`P= 100 W`
`R= (V^2)/(P)`
` = ((220xx220))/(100)`
`=((22 xx 22)) Omega`
`P= 150 W`
`=sqrt(pR = sqrt(150xx22xx22)`
`=22xxsqrt(150) = 269.4`
` =270V`