A magnetic field of `(4.0 X10^(-3)vec k)` T exerts a force of `(4.0veci +3.0vecj x 10^(-10)` N on a particle having a charge of `1.0X10^(-9)` C and going in the x-y plane. Find the velocity of the particle.

Explanation

` B = (4 xx 10 ^-8) vecK )T , `
`F = [4 veci + 3 veci ] xx 10^(-10) N , `
`Fx = 4 xx 10^(-4) N , `
Fy = 3 xx 10^(-10) N ,`
` q = 1 xx 10 ^(-8)C `
Considering to motion along x- axis:
` Fx = qu(V_y)B `
rArr ` Vy =100 m/s (J)`
along y-axis
Fy = qu xx B rArr Vx = 75 m/s`
Veloncity `= (-75 veci + 100 veci ) m/s`