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A long solenoid is formed by winding 20 ...

A long solenoid is formed by winding 20 turns `cm^-1`. What current is necessary to produce a magnetic field of 20 mT inside the solenoid?

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Solution: The magnetic field inside the solenoid is
` B = (mu_0) ni`
` or, 20 xx 10^-3 T = (4 pi xx (10^-7) TmA^-1) xx (20 xx ((10^2)m^-1) i`
` or, i=8*0A.`
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HC VERMA-MAGNETIC FIELD DUE TO CURRENT-Exercises
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  2. Using the formulae ((vecF)=(vec qv)xx (vec B) and (B= (mu0)i/2pi r ), ...

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  3. A current of 10A is established in a long wire along the positive z-ax...

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  7. A long, straight wire of radius r carries a current i and is placed ho...

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  9. A long vertical wire carrying a current of 10A in the upward direction...

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  11. Two parallel wires carry equal currents of 10A along the same directio...

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  12. Two long, straight wires, each carrying a current of 5A, are placed al...

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  13. Four long, straight wires, each carrying a current of 5.0 A, are place...

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  14. Figure shows a long wire bent at the middle to form a right angle. Sho...

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  15. Consider a straight piece of length x of a wire carrying a current i. ...

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  16. Consider a 10-cm long piece of a wire which carries a current of 10A ....

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  17. A long, straight wire carries a current i. Let B1 be the magnetic fiel...

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  18. Figure shows a square loop ABCD with edge length a. The resistance of ...

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  19. Figure shows a square loop of edge a made of a uniform wire. A current...

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  20. Consider the situation described in the previous problem. Suppose the ...

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  21. The wire ABC shown in figure forms an equilateral triangle. Find the m...

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