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In Ampere's law (oint (vec B).(vec dl))=...

In Ampere's law `(oint (vec B).(vec dl))=(mu_0)I`, the current outside the curve is not included on the right hand side. Does it mean that the magnetic field B calculated by using Ampere's law , gives the contribution of only the currents crossing the area bounded by the curve?

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Explain : "For some uses Ampere's circuital law ointvecB*vec(dl)=mu_(0)I is easy".

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Verify the Ampere's law for magnetic field of a point dipole of dipole moment overset(to)(M) = M hat(k) . Take C as the closed curve running clockwise along (i) the z-axis from z=a gt 0 to z= R, (ii) along the quarter circle of radius R and centre at the origin, in the first quadrant of x-z plane, (iii) along the x-axis from x = R to x = a and (iv) along the quarter circle of radius a and centre at the origin in the first quadrant of x-z plane.

Do magnetic forces obey Newton's third law. Verify for two current elements vec(dl_(1))=dl(hati) located at the origin and vec(dl_(2))=dl(hatj) located at (0, R, 0). Both carry current I.