A copper wire of diameter 1.6 mm carries a current of 20A. Find the maximum magnitude of the magnetic field `(vec B)`due to this current.

Explanation

Here diameter `= 1.6xx10^(-3)m`
`. `:. Radius = 0.8xx10^(-3) m`
`. we know B = (mu0 i)/(2pir)`
` `=(2xx10^(-7)xx 20)/(0.8xx10^(-3) = 5mt`