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Consider the circuit shown in the slidin...

Consider the circuit shown in the sliding contact is being pulled towards right so that the resistance in the circuit is increasing. Its valve at the instant shown in `12 Omega`. Will the current be more then 0.50 A or less than it at this instant?

Text Solution

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As the sliding contact is being pulled, the current in the circuit changes
An induced emf`varepsilon =- L(di)/(dt) is produced across the inductor
The net emf in the circuit is `6 V - L (di)/(dt)` and hence the current is ` i= (6 V - L(di)/(dt))/(12 Omega) at the instant shown
now the resistance in the circuit is increasing, the current is decreasing and `so(di)/(dt)` is nagative thus, the numerator of (i) is more then 6 V and hence i is greater then `(6 V)/ (12 Omega) =0
50 A .
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