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Find the total heat produced in the loop...

Find the total heat produced in the loop of the previous problem during the interval 0 to 30 s if the resistance of the loop is `4.5 mOmega.

Text Solution

Verified by Experts

As heat product is a scalar property:
so, net heat produced
`=H_a+H_b+H_c+H_d`
`R=42m Omega =405xx10^(-3) Omega`
`(a) e=3xx10^(-4)V`
`i=e/R=(3xx10^(-4))/(4.5xx10^(-3))`
`=6.7xx10^(-2) Amp.`
`H_a=(6.7xx10^(-2)^2)xx4.5xx10^(-3)xx5`
`H_b=H_d=0`
`[Since emf is induced for 5 sec]`
`H_c=(6.7xx10^(-2))^2xx4.5xx10^(-2)xx5`
`So, total heat `
`=H_a+H_c`
`=2xx(6.7xx10^(-2))^2xx4.5xx10^(-3)xx5`
`=2xx10^(-4) J.`
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