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An inductor (L = 200 mH) is connected to...

An inductor `(L = 200 mH)` is connected to an `AC` source of peak `emf 210 V` and frequency `50 Hz`. Calculate the peak current. What is the instantaneous voltage of the source when the current is at its peak value?

Text Solution

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The rms current is
`i_(rms) = i_0/sqrt(2) = 3.5 A`.
The time period is
`T = 1/v = 1/60 s`.
The current takes one fourth of the time period to reach the peak value starting from zero. Thus, the time required is
`t = T/4 = 1/240 s`.
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