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An electromagnetic wave going through va...

An electromagnetic wave going through vacuum is described by
` E= E_0 sin(kx- omega t), B=B_0sin(kx-omega t)`.
Then

A

`(E_0)k =(B_0)omega`

B

`(E_0) (B_0)=omega k`

C

`(E_0)omega = B_0 k `

D

none of these .

Text Solution

Verified by Experts

The correct Answer is:
A
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