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A hydrogen atom moving at a speed v abso...

A hydrogen atom moving at a speed v absorbs a photon of `lamda` nm and stops. Find value of v. Mass of hydrogen atom is m :

Text Solution

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The energy of each photon is
` E = (hc/lambda)`
` = ((6.63 xx (10^-34)J s) xx (3 xx (10^8)m (s^-1))/ (632.8 xx (10^-9)m))`
` = (3.14 xx (10^-9)m).`
The energy of the laser emitted per second is
` (5 xx (10^-3)J). Thus the number of photons emitted per`
second
` (5 xx (10^-3)J/ 3.14 xx (10^-19)J) = 1.6 xx (10^16).
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