Home
Class 12
PHYSICS
Ultraviolet light of wavelength 280 nm i...

Ultraviolet light of wavelength 280 nm is used in an
experiment on photoelectric effect with lithium
`( varphi = 2.5 eV)` cathode. Find (a) the maximum kinetic
energy of the photoelectrons and (b) the stopping
potential.

Text Solution

Verified by Experts

(a) The maximum kinetic energy is
` K_max = (hc/lambda)- varphi. `
`= (1242 eV nm/ 280 nm)- 2.5 eV. `
` = 4.4 eV - 2.5 eV = 1.9eV. `
(b) Stopping potential V is given by
` eV= K_max`
` or, V=(K_max)/e = 1.9 eV/e = 1.9 V.`
Promotional Banner

Topper's Solved these Questions

  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA|Exercise Short Answer|13 Videos
  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA|Exercise Objective 1|14 Videos
  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA|Exercise Worked Out Examples|4 Videos
  • PERMANENT MAGNETS

    HC VERMA|Exercise Exercises|25 Videos
  • PHOTOMETRY

    HC VERMA|Exercise Exercises|16 Videos

Similar Questions

Explore conceptually related problems

The photoelectric cutoff voltage in a certain expertiment is 1.5 V.What is the maximum kinetic energy of photoelectrons emitted?

The photoelectric cut-off voltage in a certain experiment is 1.5 v. What is the maximum kinetic energy of photoelectrons emitted?

A:Value of stopping potential depend on frequency of incident light and independent of intensity of light. R:Maximum kinetic energy of photoelectron is proportional to stopping potential .

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

Statement - 1 : When ultraviolet light is incident on a photocell , its stopping potential is V_(0) and the maximum kinetic energy of the photoelectrons is K_(max) when the ultraviolet light is replaces by X- rays both V_(0) and K_(max) increase Statement - 2 : Photoelectrons are emitted with speeds ranging from zero to a maximum value became of the range of frequencies present in the incident light

The work function of caesium metal is 2.14 ev. When light of frequency 6 xx10^(14)Hz is incident on the metal surface, photoemission of electrons occurs. What is the (a) maximum kinetic energy of the emitted electrons, (b) Stopping potential, and (c) maximum speed of the emitted photoelectrons?

An electron and a photon each have a wavelength of 1.00 nm. Find (a) their momentum , (b) the energy of the photon and (c) the kinetic energy of electron.

The work function of caesium metal is 2.14 eV.When light of frequency 6xx10^(14) Hz is incident on the metal surface ,photoemission of electrons occurs.What is the (a)Maximum kinetic energy of the emitted electrons. (b)Stopping potential ,and (c )Maximum speed of the emitted photoelectrons?

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect.When light from this spectral (cutoff)potential of photoelectrons is 0.38 V.Find the work function of the material from which the emitter is made.

A certain metallic surface is illuminated with monochromatic light of wavelength lambda .The stopping potentail for photelectric current for this light is 3V_(0) .If the same surface is illuminated with light of wavelength 2lambda ,the stopping potential is V_(0) .The threshold wavelength for this surface for photoelectric effect is