The work function of a metal is ` 2,5 xx (10^-19) J`. (a) Find the threshold frequency for photoelectric emission. (b) If the metal is exposed to a light beam of frequency `(6.0 xx 10^14)` Hz, what will be the stopping potential ?
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Given ` W_0 = 2.5 xx 10^(-19) J ` (a) we have `W_0 = hv_0` or ` V_0 = W_0 / h ` `= 2.5 xx 10^(-19) / 6.063 xx10^(-34) ` `= 3.77 xx 10^(14) Hz` `= 3.8 xx 10^(14) Hz` (b) ` eV_0 = hv - W_0 ` or, V_0 = hv - W_0 / e ` ` = 6.63 xx 10^(-34) xx 6 xx 10^(14) - 2.5 xx 10^(-19) / 1.6 xx 10^(-19) ` `= 6.97 xx 10^(-19) - 2.5 xx 10^(-19) / 1.6 xx 10^(19) ` `0.91 V`
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