Calculate the energy of a `He^(+)ion` in its first excited state solution

Explanation

The energy is `E_(0) = (-RhcL^(2))/(n^(2)) = -((13.6eV)Z^(2))/(n^(2))`
For a `He^(+) ion, Z = 2` and the for the first excited state ` n = 2` so that the energy of `He^(+)` ion in the first excited state is `- 13.6eV`