Find the current through the resistance in the circuits shown in figure

Explanation

(a) Since both the diodes are forward biased, n et resistance `= 2Omega`
`i = 2V/(2Omega) = 1A` (brgt One of the diodes is forwad biased and other is reverse thus the resitance of one becomes`oo`
`:. i = (2)/(2+oo) = 0A`
Both are forwad biassed .Thus the resistance is 0
`I = (2)/(2) = 1A`
Once is forwad and other is reverse biased.
Thus the current passed through the forward biased diode.
`:. i = (2)/(2) =1A`