Home
Class 12
PHYSICS
^32P beta-decays to ^32S.Find the sum of...

`^32P` beta-decays to `^32S`.Find the sum of the energy of the antineutrino and the kinetic energy of the `beta-particle`. Neglect the recoil of the daughter nucleus. Atomic mass of `^32P=31.974 u` and that of `^32S=31.972 u`.

Text Solution

Verified by Experts

The correct Answer is:
A

`p^(32) rarr S^(32) + _1v^0 + _(-1)beta^0`
Energy of antineutrino and `beta-particle`
`= (31.974 - 31.972)u`
`= 0.002u`
`=0.002 xx 931= 11.862 MeV` .
Promotional Banner

Topper's Solved these Questions

  • THE NUCLEOUS

    HC VERMA|Exercise Objective 2|10 Videos
  • SPEED OF LIGHT

    HC VERMA|Exercise Exercises|3 Videos
  • THE SPECIAL THEORY OF RELATIVITY

    HC VERMA|Exercise Exercises|27 Videos

Similar Questions

Explore conceptually related problems

Separation of Motion of a system of particles into motion of the centre of mass and motion about the centre of mass : (a) Show p=p_(i).+m_(i)V where p_(i) is the momentum of the ith particle (of mass m_(i) ) and p_(i).=m_(i)v_(i). . Note v_(i). is the velocity of the i^(th) particle relative to the centre of mass Also, prove using the definition of the centre of mass Sigmap_(i).=0 (b) Show K=K.+(1)/(2)MV^(2) where K is the total kinetic energy of the system of particles, K. is the total kinetic energy of the system when the particle velocities are taken with respect to the centre of mass and (1)/(2)MV^(2) is the kinetic energy of the translation of the system as a whole (i.e. of the centre of mass motion of the system). The result has been used in Sec. 7.14). (c ) Show vecL=vecL.+vecRxxvec(MV) where vecL.=Sigmavec(r_(i)).xxvec(p_(i)). is the angular momentum of the system about the centre of mass with velocities taken relative to the centre of mass. Remember vec(r._(i))=vec(r_(i))-vecR , rest of the notation is the velcities taken relative to the centre of mass. Remember vec(r._(i))=vec(r_(i))-vecR rest of the notation is the standard notation used in the chapter. Note vecL , and vec(MR)xxvecV can be said to be angular momenta, respectively, about and of the centre of mass of the system of particles. (d) Show vec(dL.)/(dt)=sumvec(r_(i).)xxvec(dp.)/(dt) Further, show that vec(dL.)/(dt)=tau._(ext) where tau._(ext) is the sum of all external torques acting on the system about the centre of mass. (Hint : Use the definition of centre of mass and Newton.s Thrid Law. Assume the internal forces between any two particles act along the line joining the particles.)

The nucleus ""_(10)^(23)Ne decays by beta^(-) – mission. Write down the beta -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that: m (""_(10)^(23)Ne ) = 22.994466 u m (""_(11)^(23)Na ) = 22.989770 u.

The mass of a nucleus ._(Z)^(A)X is less that the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus.The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m_(1) and m_(2) only if (m_(1)+m_(2)) lt M . Also two light nuclei of masses m_(3) and m_(4) can undergo complete fusion and form a heavy nucleus of mass M'. only if (m_(3)+m_(4)) gt M' . The masses of some neutral atoms are given in the table below: |{:(._(1)^(1)H ,1.007825u , ._(1)^(2)H,2.014102u,._(1)^(3)H,3.016050u,._(2)^(4)He,4.002603u),(._(3)^(6)Li,6.015123u,._(3)^(7)Li,7.016004u,._(30)^(70)Zn,69.925325u, ._(34)^(82)Se,81.916709u),(._(64)^(152)Gd,151.91980u,._(82)^(206)Pb,205.974455u,._(83)^(209)Bi,208.980388u,._(84)^(210)Po,209.982876u):}| Taking kinetic energy ( in KeV ) of the alpha particle, when the nucleus ._(84)^(210)P_(0) at rest undergoes alpha decay, is:

A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16].

The figure shows a snap photograph of a vibrating string at t = 0 . The particle P is observed moving up with velocity 20sqrt(3) cm//s . The tangent at P makes an angle 60^(@) with x-axis. (a) Find the direction in which the wave is moving. (b) Write the equation of the wave. (c) The total energy carries by the wave per cycle of the string. Assuming that the mass per unit length of the string is 50g//m .

The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with velocity of 2 m/s without slipping is 32.8 J. The radius of gyration of a body is ………..

The isotope _(5)^(12) B having a mass 12.014 u undergoes beta - decay to _(6)^(12) C _(6)^(12) C has an excited state of the nucleus ( _(6)^(12) C ^(**) at 4.041 MeV above its ground state if _(5)^(12)E decay to _(6)^(12) C ^(**) , the maximum kinetic energy of the beta - particle in unit of MeV is (1 u = 931.5MeV//c^(2) where c is the speed of light in vaccuum) .

Consider the decay of a free neutron at rest : n to p +e^(-) Show that the two body decay of this type must necessary give an electron of fixed energy and therefore cannot account distribution in the beta - decay of a neutron or a nucleous as shown in figure . [ Note : The simple result of this exercise was one among the several arguments advanced by W . Pauli to perdict the existence of a third particle in the decay products of beta - decay . This particle is known as neutrino spin 1/2 ( like e^(-) p or n ) but is neutral ad either massless or having an extremely small mass (compared to the mass of electron) and which interacts very weakly with matter . The correct decay process of neutron is : n to p+e(-)+v)

HC VERMA-THE NUCLEOUS-Exercises
  1. Show that the minimum energy needed to sepatate a proton from a nucleu...

    Text Solution

    |

  2. Calculate the minimum energy needed to separate a neutron form a nucle...

    Text Solution

    |

  3. ^32P beta-decays to ^32S.Find the sum of the energy of the antineutrin...

    Text Solution

    |

  4. A free neutron beta-decays to a proton with a half-life of 14 minutes ...

    Text Solution

    |

  5. Complete the following decay schemes. (a)88^226Ra rarr alpha + (b)8^19...

    Text Solution

    |

  6. In the decay ^64(Cu) rarr ^64(Ni)+e^+v,the maximum kinetic energy carr...

    Text Solution

    |

  7. Potassium-40 can decay in three modes .It can decay by beta^(-) -emiss...

    Text Solution

    |

  8. Lithium (Z=3) has two stable isotopes ^6Liand ^7Li.When neutrons are b...

    Text Solution

    |

  9. The masses of "^11C and "^11B are respectively 11.0114 u and 11.0093 u...

    Text Solution

    |

  10. ^228Themits an alpha particle to reduce to ^224Ra.Calculate the kineti...

    Text Solution

    |

  11. Calculate the maximum kinetic energy of the bera particle emitted in t...

    Text Solution

    |

  12. The decay constant of 80^197Hg(electron capature to 79^197Au)is 1.8xx1...

    Text Solution

    |

  13. The half-life of .^198Au is 2.7 days. Calculate (a) the decay constant...

    Text Solution

    |

  14. Radioactive 138I has a half-life of 8.0 days .A sample containing 138I...

    Text Solution

    |

  15. The decay constant of ^238Uis 4.9xx10^-18 s^-1.(a) What is the avarage...

    Text Solution

    |

  16. A certain sample of a radioactive marerial decays at the rate of 500 p...

    Text Solution

    |

  17. the count rate from a radioactive sample falls from 4.0xx10^6per secon...

    Text Solution

    |

  18. The half-life of ^226Ra is 1602 y.Calculate the activity of 0.1g of Ra...

    Text Solution

    |

  19. The half-life of a radioisotope is 10 h . Find the total number of dis...

    Text Solution

    |

  20. The selling rate of a radioactive isotope is decided by its activity. ...

    Text Solution

    |