निम्न यौगिकों के आण्विक द्रव्यमान का परिकलन कीजिएः
`H_(2), O_(2), Cl_(2), CO_(2),CH_(4),C_(2)H_(6),C_(2)H_(4),NH_(3)` एवं `CH_(3)OH`

Explanation

`H_(2) = 2H = 2 xx 1 = 2 u`
`O_(2) = 2O = 2 xx 16 = 32u`
` Cl_(2) = 2Cl = 2 xx 35.5 = 71 u`
`CO_(2) = C + 2O = 12+2 xx 16 = 12 + 32 = 44 u`
` CH_(4) = C + 4H = 12 + 2 xx 16 = 12 + 32 = 44 u`
`C_(2)H_(6) = 2C + 6H = 2 xx 12 + 4 xx 1 = 24 + 4 = 28 u`
`NH_(3) = N + 3H = 14 + 3 xx 1 = 14 + 3 = 17 u`
`CH_(3) OH = C + 3H + O + H = 12 + 3 xx 1 + 16 + 1 = 12+3+16+1 = 32 u`