Home
Class 12
CHEMISTRY
A metal has a fcc lattice. The edge leng...

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is `2.72 g cm^(-3)`. The molar mass of the metal is
`(N_A,"Avogadro's constant"=6.02 X10^23 mol^(-1))`

A

`40 g mol^(-1)`

B

`30 g mol^(-1)`

C

`27 g mol^(-1)`

D

`20 g mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

An element crystallized in fcc lattice and edge length of unit cell is 400 pm. If density of unit cell is 11.2 g cm^(-3) , then atomic mass of the element is

An element crystallizes in fcc lattice. If the edge length of the unit cell is 408.6 pm and the density is 10.5 g cm^(-3) . Calculate the atomic mass of the element.

b) An element crystallizes in a foc lattice. The edge length of the unit cell is 400 pm. Calculate the density of the unit cell. ("molar mass"="60 g mol"^(-1)) ("Avogadro number"=6.02 xx 10^(23))

A metallic element 'X' has cubic lattic. Each edge of the unit cell is 2.0Å and its density is 2.5 g cm^(-3) . Number of atoms in 200g of the metal are :

A metallic element exists as a cubic lattice. Each edge of the unit cell is 2.88 Å . The density of the metal is 7.20 g cm^(-3) . How many unit cells there will be in 100g of the metal?

A metal X ( at. Mass = 60) has a body centred cubic crystal structure. The density of the metal is 4.2 g cm^(-3) . The volume of unit cell is

The edge length of unit cell of a metal (Mw = 24) having cubic structure is 4.53 Å . If the density of metal is 1.74 g cm^(-3) , the radius of metal is (N_(A) = 6 xx 10^(23))

An element having atomic mass 60 amu. has fcc unit cell. The edge length of the unit cell is 4 xx 10^(2) pm. Find the density of the unit cell.

Silver crystallizes in CCP lattice. The edge length of its unit cell is 408.6 pm. Calculate density of silver (atomic mass of silver is 107.9)