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Given : E(Fe^(3+)//Fe)^@=-0.036V E(Fe^(...

Given : `E_(Fe^(3+)//Fe)^@=-0.036V`
`E_(Fe^(2+)//Fe)^@ = -0.439 V`
The value of standard electrode potential for the chance , `Fe_(aq)^(3+) +e^- rarr Fe_(aq)^(2+) ` will be :

A

0.770 V

B

`-0.270 V`

C

`-0.072 V`

D

`0.385 V`

Text Solution

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The correct Answer is:
A
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