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To neutralize completely 20 mL of 0.1 M ...

To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorus `(H_(3)PO_(3))` acid the volume of 0.1 M aqueous KOH solution required is

A

60mL

B

20mL

C

40moL

D

10mL

Text Solution

Verified by Experts

The correct Answer is:
C
Apply `N_(1)V_(1)=N_(2)N_(2)`
`M_(1)xxunderset(("Acid"))(n_(1))xxv_(1)=M_(2)xxunderset(("base"))(n_(2))xxv_(2)`
`impliesv_(2)=40ml`
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