Benzene can be produced from hexane in the reversible reaction:
`C_(6)H_(14) (g) The partial pressure equilibrium constant (Kp) for this reaction has been found to vary with temperature according to the equation.
`log K_(p) = 23.45 - (13941 K)/T`
Equilibrium is established by starting with pure `C_6H_14` gas. What must be the temperature if the initial gas pressure is 1 atm and the equilibrium partial pressure of `H_2` is 1 atm.

Answer

598

Explanation

`{:(,C_(6)H_(14)(g) `K_(p) = (P_(H_(2)(g)))^(4)/(P_(C_(6)H_(4)(g))) = 1^(4)/(3//4) = 4/3`
`log K_(P) = 23.45 - 13941/T = log 4/3`
`23.45- 13941/T = 0.6020 - 0.4777 = 0.1243`
`T = 13941/(23.3257) = 597.6 K`