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The rate constant for the reaction, 2N...

The rate constant for the reaction,
`2N_2O_5 + 4NO_2 + O_2` is `3.0 xx 10^(-5) sec^(-1)`
If the rate is `2.40 xx 10^(-5) M sec^(-1)`,then the concentration of `N_2O_5` (in M) is :

A

`1.4 `

B

`1.2 `

C

`0.04 `

D

`0.8 `

Text Solution

Verified by Experts

The correct Answer is:
D
`r = K [N_2O_5]` I order as unit of `k = sec^(-1)`
` 2.40 xx 10^(-5) = 3.0 xx 10^(-5) [N_2O_5] `
`therefore [N_2O_5] = (2.40)/(3.0) = 0.8 M `
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