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The expression 3[sin^4((3pi)/2+alpha)+si...

The expression `3[sin^4((3pi)/2+alpha)+sin^4((3pi)+alpha)] ` is -2
`[sin^6(pi/2+alpha)+sin^6(5pi-alpha)]` equal to

A

0

B

1

C

3

D

`sin 4alpha+cos 6alpha`

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The correct Answer is:
B
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NTA MOCK TESTS-NTA TPC JEE MAIN TEST 68-MATHEMATICS
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