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The dimensional formula for magnetic flu...

The dimensional formula for magnetic flux is

A

`[ML^(2)T^(-2)A^(-1)]`

B

`[ML^(3)T^(-2)A^(-2)]`

C

`[M^(0)L^(-2)T^(-2)A^(-2)]`

D

`[ML^(2)T^(-1)A^(2)]`

Text Solution

Verified by Experts

The correct Answer is:
A
Magnetic flux is given as
`phi=B S cos theta `……….i
Here is B magnetic field and S is area.
Magnetic force F on a charge q moving with velocity v is given as
`F=qvBsin beta`
So `B=F/(q v sin beta)` ……….ii
By equation I and ii
`phi=F/(qvsin beta)xxS cos theta`
Trigonometric functions are dimensitons so
`[phi]=[(FS)/(qv)]=(MLT^(-2)xxL^(2))/(ATxxLT^(-1))`
`=ML^(2)T^(-2)A^(-1)`
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Knowledge Check

  • The dimensional formula of magnetic flux is :

    A
    `[ML^2 T^(-2) A^(-1)]`
    B
    `[ML^0 T^(-2) A^(-2)]`
    C
    `[M^0 L^(-2) T^(-2) A^(-2)]`
    D
    `[ML^2T^(-1) A^3]`

  • Dimensional formula of magentic flux is

    A
    `ML^(2) T^(-2) A^(-1)`
    B
    `ML^(2) T^(-2) A^(-2)`
    C
    `M^(0) L^(-2) A^(-3)`
    D
    `ML^(2) T^(-2) A^(3)`

  • The dimensional formula of magnetic flux density is :

    A
    `M^(1)L^(2)T^(1)I^(-1)`
    B
    `M^(1)T^(-2)I^(-1)`
    C
    `M^(1)L^(2)T^(-2)I^(-1)`
    D
    `M^(1)L^(1)T^(-2)I^(-1)`

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