Consider a horizontal water pipe connected to a pressure meter. When the pipe is closed the pressure displayed is `4.5xx10^(5)Nm^(-2)` and when the pipe is openekd the pressure displayed is `4xx10^(5)Nm^(-2)`. Then what is the speed of the water (in standard units) flowing in the pipe ?

Answer

`10.00`

Explanation

For flow of water along a horizontal pipe
`(P_(1))/(rho)+1/2v_(1)^(2)+(P_(2))/(rho)+1/2v_(2)^(2)`
`(4.5xx10^(5))/1000+1/2(0)^(2)=(4xx10^(5))/1000+1/2v_(2)^(2)`
`1/2v_(2)^(2)=((4.5xx10^(5))/1000-(4xx10^(5))/1000)`
`1/2v_(2)^(2)=((4.5xx10^(5))/1000-(4xx10^(5))/1000)`
`v_(2)=sqrt((2xx0.5xx10^(5))/1000)`
`=sqrt((2xx0.5xx10^(5))/1000)`
`:.v_(2)=10ms^(-1)`