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Find the binding energy of helium nuclei...

Find the binding energy of helium nuclei if masses of a helium nucleus, proton and neutronare 4.0015u,1.0073u and 1.0087u respectively

A

`0.0305J`

B

`0.0305erg`

C

`28.4MeV`

D

`0.061u`

Text Solution

Verified by Experts

The correct Answer is:
C
Helium nuclei `(He_(2)^(4))` has 2 prontons and 2 neutrons
Mass defect
=
[ Total mas sof pprotons `+` total mss of neutrons) `-` total mass of nuclei
`Deltam`
`=[(2xx1.0073)+(2xx1.0087)]-4.0015=0.0305`
Now binding energy =mass defect `xx931.5`
`Deltam=0.0305xx931.5=28.4077`
`~~28.4` Mev
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