Current I flows through a long conducting wire bent at right angle as shown in Fig. Find the magnetic field at point P on the right angle bisector of the angle XOY at distance r form O.

Options

A. `(mu_(0)I)/(pir)T`
B. `(2mu_(0)I)/(pir)T`
C. `(mu_(0)I)/(4pi)(sqrt(2)+1)T`
D. `(mu_(0))/(4pi)xx(2I)/r(sqrt(2)+1)T`

Answer

D

Explanation

`B=2[(mu_(0)I)/(4pi)r/(sqrt(2))(sin 45^(@)+sin90^(@))]`
`B=(mu_(0))/(4pi)xx(2I)/r(sqrt(2)+1)T`