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One mole of an ideal diatomic gas underg...

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure,

The change in internal energy of the gas during the transition is :

A

`-20kJ`

B

`20J`

C

`-12kJ`

D

`20kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaU=muC_(v)DeltaT` and `T=(PV)/(muR)`
so `DeltaT=T_(2)-T_(1)=(P_(2)V_(2)-P_(1)V_(1))/(muR)`
so `DeltaU=(muR)/(gamma-1)((P_(2)V_(2)-P_(1)V_(1))/(muR))=(P_(2)V_(2)-P_(1)V_(1))/(gamma-1)`
`impliesDeltaU=(-8xx10^(3))/(2//5)=-20kJ`
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