A body A, oFIGURE m=0.1 kg has a initial velocity oFIGURE`3hatikms^(-1)`. It collides elastically with another body. B oFIGURE the same mass which has an initial velocity oFIGURE `5hatjms^(-1)`. AFIGUREter collision, A moves with a velocity `vec(v)=4(hati+hatj)`. The energy oFIGURE B aFIGUREter collision is written as `(x)/(10)J`. The value oFIGURE x is _.

Answer

`1`

Explanation

`KE_(1)+KE_(1)` for
`1/2mxx25+1/2xxmxx9=1/2xx32`
`=1/2mv^(2)`
`34=32+v^(2)`
`KE=1/2xx0.1xx2=0.1J=1/10`
`x=1`
elastic collision