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An object is dragged along a horizontal ...

An object is dragged along a horizontal surface by the machine which delivers a constant power. How does the distance moved by the object is dependent on time, t ?

A

`t^(3//4)`

B

`t^(3//2)`

C

`t^(1//4)`

D

`t^(1//2)`

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The correct Answer is:
To determine how the distance moved by an object, \( s \), is dependent on time, \( t \), when the object is dragged by a machine delivering constant power, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Power**: The power \( P \) delivered by the machine is constant. Power is defined as the product of force \( F \) and velocity \( v \): \[ P = F \cdot v \] 2. **Relating Force and Acceleration**: According to Newton's second law, force can also be expressed as: \[ F = m \cdot a \] where \( m \) is the mass of the object and \( a \) is its acceleration. 3. **Expressing Velocity**: The velocity \( v \) of the object can be expressed in terms of acceleration and time: \[ v = u + at \] Given that the initial velocity \( u = 0 \) (the object starts from rest), this simplifies to: \[ v = at \] 4. **Substituting into Power Equation**: Substituting \( F = m \cdot a \) and \( v = at \) into the power equation gives: \[ P = m \cdot a \cdot (at) = m \cdot a^2 t \] 5. **Solving for Acceleration**: Rearranging the equation to solve for acceleration \( a \): \[ a = \sqrt{\frac{P}{m t}} \] 6. **Using the Kinematic Equation**: The distance \( s \) traveled by the object can be calculated using the equation: \[ s = ut + \frac{1}{2} a t^2 \] Since \( u = 0 \), this simplifies to: \[ s = \frac{1}{2} a t^2 \] 7. **Substituting for Acceleration**: Substituting the expression for \( a \) into the distance equation: \[ s = \frac{1}{2} \left( \sqrt{\frac{P}{m t}} \right) t^2 \] This can be simplified to: \[ s = \frac{1}{2} \sqrt{\frac{P}{m}} t^{3/2} \] 8. **Final Relationship**: Thus, we find that the distance \( s \) is proportional to \( t^{3/2} \): \[ s \propto t^{3/2} \] ### Conclusion: The distance moved by the object is dependent on time \( t \) as: \[ s \propto t^{3/2} \]

To determine how the distance moved by an object, \( s \), is dependent on time, \( t \), when the object is dragged by a machine delivering constant power, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Power**: The power \( P \) delivered by the machine is constant. Power is defined as the product of force \( F \) and velocity \( v \): \[ P = F \cdot v ...
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