A spring-block system is executing SHM. The mass of the block is M and the time period of oscillation is T. If the mass of the block is increased by m, then time period becomes `(7T)/4`. Now, find the ratio of `m/M` ,

Answer

`02.06`

Explanation

`T prop sqrt(m)`
`rArr T_(2)/T_(1) = sqrt(m_(2)/m_(1))`
`rArr 7/4 = sqrt((M+m)/M)`
`rArr 49/16 = (M +m)/M`
`rArr m/M = 49/16-1 = 3/16 = 2.06`