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A monoatomic gas expands following as th...

A monoatomic gas expands following as thermodynamic law `P=C_(1)V+C_(2)`, where `C_(1),C_(2)` are constants, from state `A(V_(0),3P_(0))` to `B(3V_(0),P_(0))`.What will be the volume of the gas upto which it absorbs heat?

A

`V_(0)`

B

`2V_(0)`

C

`2.5V_(0)`

D

`3V_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
The gas absorbs heat till
`(dP)/(dV)=-(gammaP)/V`
`-(P_(0))/(V_(0))=-5/3P/V`
`impliesP=(3P_(0))/(5V_(0))V`
Putting in the equation
`(3P_(0))/(5V_(0))V=(-P_(0))/(V_(0))+4P_(0)`
`impliesV=2.5V_(0)`
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