A bird in air looks at a fish directly below it inside in a transparent liquid in a tank. If the distance of the fish as estimated by the bird is `h_1` and that of the bird as estimated by the fish is `h_2,` then the refractive index of the liquid is

Options

A. `h_(2)/h_(1)`
B. `h_(1)/h_(2)`
C. `(h_(1) + h_(2))/(h_(1) - h_(2))`
D. `(h_(1) - h_(2))/(h_(1) + h_(2))`

Answer

A

Explanation

Distance of fish seen by bird
`h_(1) = y_(1) + y_(2)/mu`
Distance of bird seen by fish
`h_(2) = y_(2) + muy_(1)`
`muh_(1) = mu y_(1) + y_(2)`
`muh_(1) - h_(2) =0`
`mu = h_(2)/h_(1)`