Efficiency of carnot engine working between ice point and steam point is

Options

A. `24. 9%`
B. `25.7%`
C. `26.8%`
D. `28.8%`

Answer

C

Explanation

Here, ice point, `T_2 = 0^(@) C = 0 + 273 = 273 K`
and steam point, `T_1 = 100^(@)C = 100 + 273 = 373 K`
Efficiency of the carnot engine
` eta =1 - T_(2)/T_(1) = 1 - 273/373 = 100/373 = 10/373 xx 100 % = 26. 8%`