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Light from a hydrogen tube is incident o...

Light from a hydrogen tube is incident on the cathode of a photoelectric cell the work function of the cathode surface is `4.2 eV`. In order to reduce the photo - current to zero the voltage of the anode relative to the cathode must be made

A

– 4.2 V

B

– 9.4 V

C

– 17.8 V

D

`+9.4 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=W_0+eV_0`
For hydrogen, `E=+13.6 eV`
`:.+13.6=4.2+eV_0`
`implies V_0=((13.6-4.2)eV)/e=9.4 V`
Potential at anode= -9. 4 V
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